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Sum-to-product identities · derivation ·proof

Where sin A − sin B = 2 cos((A + B)/2) sin((A − B)/2) comes from

Keep the half-difference where the change is. The term with (A − B)/2 is the 'small' one; that is the factor that vanishes when A = B, which is a good sanity check.

sin A − sin B = 2 cos((A + B)/2) sin((A − B)/2)

Building it step by step

  1. Check A = B: the right side must be 0
    sin 0 = 0 kills the product ✓.
  2. So sin((A − B)/2) has to be a factor
    Structural necessity.
  3. The other factor is the cosine of the average
    Symmetry of the two angles.

How to recall it under pressure

Re-derive it from the first line rather than searching memory: start from sin(a) - sin(b) and do the one algebraic move the derivation above makes. If you need the statement itself, it is on the sum to product: sin a − sin b page.

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.2–7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error