Sum-to-product identities · derivation ·proof
Where sin A − sin B = 2 cos((A + B)/2) sin((A − B)/2) comes from
Keep the half-difference where the change is. The term with (A − B)/2 is the 'small' one; that is the factor that vanishes when A = B, which is a good sanity check.
sin A − sin B = 2 cos((A + B)/2) sin((A − B)/2)
Building it step by step
- Check A = B: the right side must be 0sin 0 = 0 kills the product ✓.
- So sin((A − B)/2) has to be a factorStructural necessity.
- The other factor is the cosine of the averageSymmetry of the two angles.
How to recall it under pressure
Re-derive it from the first line rather than searching memory: start from sin(a) - sin(b) and do the one algebraic move the derivation above makes. If you need the statement itself, it is on the sum to product: sin a − sin b page.