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Sum-to-product identities · derivation ·proof

Where sin A + sin B = 2 sin((A + B)/2) cos((A − B)/2) comes from

Average and half-difference. The pattern to remember: sum-to-product always talks about the average of the two angles and half their difference. Physically, that is the carrier frequency and the beat.

sin A + sin B = 2 sin((A + B)/2) cos((A − B)/2)

Building it step by step

  1. Take u = (A + B)/2, v = (A − B)/2
    Change of variables.
  2. Expand sin(u ± v)
    Sum and difference formulas.
  3. Add
    Odd terms cancel, even terms double.
  4. 2 sin u cos v
    Result.

How to recall it under pressure

Re-derive it from the first line rather than searching memory: start from sin(a) + sin(b) and do the one algebraic move the derivation above makes. If you need the statement itself, it is on the sum to product: sin a + sin b page.

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.2–7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error