Cofunction and even/odd identities · derivation ·proof
Where sin θ = cos(90° − θ) comes from
Measure from the other corner. The 'co-' in cosine means complement: cos θ started as 'the sine of the complement of θ'.
sin θ = cos(90° − θ)
Building it step by step
- sin of an angle = opp/hypDefinition.
- Same ratio from the other acute angleOpposite and adjacent swap roles.
- sin θ = cos(90° − θ)Name the swapped ratio.
How to recall it under pressure
Re-derive it from the first line rather than searching memory: start from sin(x) and do the one algebraic move the derivation above makes. If you need the statement itself, it is on the cofunction identity for sine page.