Sum and difference identities · derivation ·proof
Where tan(A + B) = (tan A + tan B) / (1 − tan A tan B) comes from
Force tangents to appear. The trick is the division by cos A cos B — it is what turns mixed sine/cosine products into tangents.
tan(A + B) = (tan A + tan B) / (1 − tan A tan B)
Building it step by step
- Every term should become tanGoal.
- tan = sin/cos needs a cos in the denominatorSo divide by the product cos A cos B.
- (sin A cos B)/(cos A cos B) = tan ACancellation, term by term.
How to recall it under pressure
Re-derive it from the first line rather than searching memory: start from tan(a + b) and do the one algebraic move the derivation above makes. If you need the statement itself, it is on the tangent of a sum page.