trigidentity.com

Worked example

Derive the double-angle formulas from the sum formulas

Answer

Set B = A in each sum formula; cosine then yields two further forms via sin² + cos² = 1.

Steps

  1. sin(A + B), B = A
    Specialise the sine sum. · Sine of a sum
  2. sin 2A = 2 sin A cos A
    Two identical terms.
  3. cos(A + B), B = A
    Specialise the cosine sum. · Cosine of a sum
  4. cos 2A = cos²A − sin²A
  5. sin²A = 1 − cos²A (and the reverse)
    Pythagorean substitution gives the other two forms. · Pythagorean identity
  6. cos 2A = 2cos²A − 1 = 1 − 2sin²A

Identities used

sin(A + B) = sin A cos B + cos A sin B
cos(A + B) = cos A cos B − sin A sin B
sin 2x = 2 sin x cos x
cos 2x = cos²x − sin²x
cos 2x = 2 cos²x − 1
cos 2x = 1 − 2 sin²x

Check it yourself

Open the verifier with the main identity pre-filled — substituting your own numbers into a step is the fastest way to find out which line you did not follow.

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