trigidentity.com

Worked example

Simplify √(1 − cos x) so it can be integrated

Answer

√2·|sin(x/2)| — on 0 < x < 2π the absolute value is sin(x/2)

Steps

  1. 1 − cos x = 2sin²(x/2)
    Rearrange the half-angle identity. · Half-angle identity for sine
  2. √(1 − cos x) = √(2sin²(x/2)) = √2·|sin(x/2)|
    √(u²) = |u|, not u — the absolute value is the trap in this problem.
  3. For 0 < x < 2π, x/2 ∈ (0, π) so sin(x/2) > 0
    Drop the absolute value on that interval.
  4. = √2 sin(x/2)
    Now integrable: ∫ = −2√2 cos(x/2) + C.

Identities used

sin(x/2) = ±√((1 − cos x)/2)

Check it yourself

Open the verifier with the main identity pre-filled — substituting your own numbers into a step is the fastest way to find out which line you did not follow.

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