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Double-angle identities · proof ·what it is and when to use it

Proof: cos 2x = 2 cos²x − 1

Double-angle identity for cosine (form 2) — proved by eliminate sine from form 1. Every line below says which rule it uses, so nothing has to be taken on faith.

cos 2x = 2 cos²x − 1

The proof

One substitution.

  1. cos 2x = cos²x − sin²x
  2. sin²x = 1 − cos²x
    Pythagorean identity. · Pythagorean identity
  3. cos 2x = cos²x − (1 − cos²x)
    Substitute.
  4. cos 2x = 2cos²x − 1
    Simplify.

Where the proof stops applying

Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.

The same claim, checked numerically

A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).

Both sides evaluated at the same angles — left side cos(2x), right side 2cos^2(x) - 1.
AngleLeft sideRight sideAgree
0°11yes
7.5°0.9659260.965926yes
15°0.8660250.866025yes
18°0.8090170.809017yes
22.5°0.7071070.707107yes
30°0.50.5yes

Related

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error