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Double-angle identities · proof ·what it is and when to use it

Proof: tan 2x = 2 tan x / (1 − tan²x)

Double-angle identity for tangent — proved by set b = a in the tangent sum. Every line below says which rule it uses, so nothing has to be taken on faith.

tan 2x = 2 tan x / (1 − tan²x)

The proof

One substitution in the tangent-of-a-sum identity.

  1. tan(A + B) = (tan A + tan B)/(1 − tan A tan B)
    Tangent of a sum. · Tangent of a sum
  2. B = A = x
    Specialise.
  3. tan 2x = (tan x + tan x)/(1 − tan x·tan x)
    Substitute.
  4. tan 2x = 2 tan x/(1 − tan²x)
    Simplify both parts.

Where the proof stops applying

Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.

The same claim, checked numerically

A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).

Both sides evaluated at the same angles — left side tan(2x), right side 2tan(x) / (1 - tan^2(x)).
AngleLeft sideRight sideAgree
0°00yes
7.5°0.2679490.267949yes
15°0.577350.57735yes
18°0.7265430.726543yes
22.5°11yes
30°1.7320511.732051yes

Related

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error