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Triangle identities · proof ·what it is and when to use it

Proof: A + B + C = 180°

Angles of a triangle add to 180° — proved by parallel line through the apex. Every line below says which rule it uses, so nothing has to be taken on faith.

A + B + C = 180°

The proof

Euclid's argument. It is worth reading once because it shows where the statement comes from: the parallel postulate, which is also why the angle sum of a triangle on a sphere is more than 180°.

  1. draw ℓ through C parallel to AB
    The construction Euclid uses (Elements I.32).
  2. the angle between ℓ and CA equals A; the angle between ℓ and CB equals B
    Alternate angles made by a transversal across parallel lines.
  3. A + B + C = 180°
    Those three angles lie on one side of the straight line ℓ.

The sampler checks this claim in radians: A + B + C against π, on triangles built from three corner points.

Where the proof stops applying

The variables are one triangle's angles and sides, so they obey A + B + C = 180° and the sine rule. Drop that constraint and the equation is simply not true — which is why the sampler here generates triangles rather than random numbers.

The same claim, checked numerically

A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few triangles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).

Both sides evaluated at the same triangles — left side A + B + C, right side pi (180 degrees).
Triangle (A)Left sideRight sideAgree
7.5°3.1415933.141593yes
15°3.1415933.141593yes
18°3.1415933.141593yes
22.5°3.1415933.141593yes
30°3.1415933.141593yes
37°3.1415933.141593yes

Related

sampled at 800 real trianglestriangles only: A + B + C = 180°Source: Euclid, Elements I.32 · OpenStax Precalculus, Ch. 7.4 context · revised 2026-09-28 ·how we check ·accuracy policy ·report an error