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Product-to-sum identities · trigonometric identity

sin A sin B = ½[cos(A − B) − cos(A + B)] — Product to sum: sin A sin B

sin A sin B = ½[cos(A − B) − cos(A + B)]

When to use it

Products of two sines — and, with A = B, the power-reducing formula sin²A = ½[1 − cos 2A]. Also the orthogonality relation Fourier series are built on.

Why it is true

Subtract the two cosine expansions: cos(A − B) − cos(A + B) = (cos A cos B + sin A sin B) − (cos A cos B − sin A sin B) = 2 sin A sin B, so halving the difference of the cosines gives back the product.

The full line-by-line version is on the proof page for product to sum: sin a sin b; the “how would I find this myself” version is in the derivation.

Where it comes from

A = B gives sin². Specialising this formula is the usual way to reach the sin² reduction.

  1. B = A
    Specialise.
  2. cos 0 = 1, cos 2A stays
    Simplify.
  3. sin²A = ½(1 − cos 2A)
    Power-reducing formula. · Power-reducing formula for sin²

Worked examples

Checked at these angles

Two sides of the identity evaluated with the same engine that runs the verifier. A single line disagreeing would break the build.

Both sides evaluated at the same angles — left side sin(A)sin(B), right side (cos(A - B) - cos(A + B)) / 2.
AngleLeft sideRight sideAgree
0°00yes
7.5°0.0288070.028807yes
15°0.0735090.073509yes
18°0.0954920.095492yes
22.5°0.1324530.132453yes
30°0.2033680.203368yes
37°0.2778870.277887yes
45°0.3694620.369462yes
53°0.463770.46377yes
60°0.5450070.545007yes
67.5°0.627130.62713yes
75°0.7006580.700658yes
90°0.8090170.809017yes
120°0.8085040.808504yes
135°0.6875690.687569yes
150°0.4972610.497261yes
180°00yes
210°-0.456773-0.456773yes
240°-0.673028-0.673028yes
270°-0.587785-0.587785yes
300°-0.310356-0.310356yes
330°-0.052264-0.052264yes
360°00yes

The mistake students make

Writing the sine pair as a sum of sines. A product of two sines becomes a difference of COSINES.

Try it

Category hub: Product-to-sum identities · all identities: /identities

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.2–7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error