Cofunction and even/odd identities · proof ·what it is and when to use it
Proof: cos(−θ) = cos θ
Cosine is even — proved by same reflection. Every line below says which rule it uses, so nothing has to be taken on faith.
cos(−θ) = cos θ
The proof
Read the x-coordinate off the reflected point.
- P(θ) = (cos θ, sin θ)Definition.
- P(−θ) = (cos θ, −sin θ)Reflection across the x-axis.
- cos(−θ) = cos θThe x-coordinate is unchanged — cosine is even.
Where the proof stops applying
Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.
The same claim, checked numerically
A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).
| Angle | Left side | Right side | Agree |
|---|---|---|---|
| 0° | 1 | 1 | yes |
| 7.5° | 0.991445 | 0.991445 | yes |
| 15° | 0.965926 | 0.965926 | yes |
| 18° | 0.951057 | 0.951057 | yes |
| 22.5° | 0.92388 | 0.92388 | yes |
| 30° | 0.866025 | 0.866025 | yes |
Related
- How would I find cos(−θ) = cos θ myself? — the derivation, which is a different question from the proof.
- Cosine is even: when to use it — the practical side.
- All cofunction and even/odd identities · proof index