Double-angle identities · proof ·what it is and when to use it
Proof: sin 2x = 2 sin x cos x
Double-angle identity for sine — proved by set b = a in the sum formula. Every line below says which rule it uses, so nothing has to be taken on faith.
sin 2x = 2 sin x cos x
The proof
Two lines from the sine sum identity.
- sin(A + B) = sin A cos B + cos A sin BSine of a sum. · Sine of a sum
- A = B = xSpecialise.
- sin 2x = sin x cos x + cos x sin xSubstitute.
- sin 2x = 2 sin x cos xCombine the two identical terms.
Where the proof stops applying
Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.
The same claim, checked numerically
A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).
| Angle | Left side | Right side | Agree |
|---|---|---|---|
| 0° | 0 | 0 | yes |
| 7.5° | 0.258819 | 0.258819 | yes |
| 15° | 0.5 | 0.5 | yes |
| 18° | 0.587785 | 0.587785 | yes |
| 22.5° | 0.707107 | 0.707107 | yes |
| 30° | 0.866025 | 0.866025 | yes |
Related
- How would I find sin 2x = 2 sin x cos x myself? — the derivation, which is a different question from the proof.
- Double-angle identity for sine: when to use it — the practical side.
- All double-angle identities · proof index