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Double-angle identities · proof ·what it is and when to use it

Proof: sin 2x = 2 sin x cos x

Double-angle identity for sine — proved by set b = a in the sum formula. Every line below says which rule it uses, so nothing has to be taken on faith.

sin 2x = 2 sin x cos x

The proof

Two lines from the sine sum identity.

  1. sin(A + B) = sin A cos B + cos A sin B
    Sine of a sum. · Sine of a sum
  2. A = B = x
    Specialise.
  3. sin 2x = sin x cos x + cos x sin x
    Substitute.
  4. sin 2x = 2 sin x cos x
    Combine the two identical terms.

Where the proof stops applying

Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.

The same claim, checked numerically

A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).

Both sides evaluated at the same angles — left side sin(2x), right side 2 sin(x) cos(x).
AngleLeft sideRight sideAgree
0°00yes
7.5°0.2588190.258819yes
15°0.50.5yes
18°0.5877850.587785yes
22.5°0.7071070.707107yes
30°0.8660250.866025yes

Related

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7.3 · Paul's Online Math Notes · revised 2026-09-26 ·how we check ·accuracy policy ·report an error