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Cofunction and even/odd identities · proof ·what it is and when to use it

Proof: tan(−θ) = −tan θ

Tangent is odd — proved by quotient of an odd and an even function. Every line below says which rule it uses, so nothing has to be taken on faith.

tan(−θ) = −tan θ

The proof

Derived in two lines from the quotient identity.

  1. tan(−θ) = sin(−θ)/cos(−θ)
    Quotient identity. · Quotient identity (tangent)
  2. = −sin θ/cos θ
    Sine is odd, cosine is even. · Sine is odd, Cosine is even
  3. = −tan θ
    Quotient identity again, backwards.

Where the proof stops applying

Both sides are undefined at the same angles — where a denominator in the proof reaches zero (for instance cos x = 0 in a tangent or secant form). Elsewhere the argument above holds for every real angle.

The same claim, checked numerically

A proof is not the same thing as a check, and this page shows both: the reasoning above, and the first few angles fed to the same engine behind the verifier. If they ever disagreed, the data would be broken — the build would fail before publishing (accuracy policy).

Both sides evaluated at the same angles — left side tan(-t), right side -tan(t).
AngleLeft sideRight sideAgree
0°00yes
7.5°-0.131652-0.131652yes
15°-0.267949-0.267949yes
18°-0.32492-0.32492yes
22.5°-0.414214-0.414214yes
30°-0.57735-0.57735yes

Related

sampled at 800 random anglesSource: OpenStax Precalculus, Ch. 7 · Paul's Online Math Notes, Trig Cheat Sheet · revised 2026-09-26 ·how we check ·accuracy policy ·report an error